Why the mean is logarithmic

Heat exchanger duty is the product of three things: how well heat crosses the surface, how much surface there is, and how hard the temperature difference is pushing.

Unlock every calculator on this site

One form unlocks all of our calculators for 90 days. The calculators run entirely in your browser: we do not store, log or transmit any values you type into them. Only the contact details in this form are sent to us.

By submitting this form you agree that Paul Industries may contact you by email about our products and services. We do not sell your details.

Q = U × A × LMTD × F

The driving force is a log mean rather than a simple average because the gap between the two streams does not close at a constant rate. Transfer is fastest where the streams are furthest apart, so the difference collapses quickly at one end and slowly at the other. Taking the arithmetic average of the two end differences always overstates the true driving force, and therefore always undersizes the exchanger.

LMTD = (ΔT₁ — ΔT₂) / ln(ΔT₁ / ΔT₂)

Counterflow LMTD for representative process duties (°F)
Duty Hot in / out Cold in / out ΔT hot end ΔT cold end LMTD
Clean steam heating WFI 250 / 250 70 / 175 75 180 119.9
Hot water to process water 180 / 140 60 / 120 60 80 69.5
Cooling a batch with chilled water 150 / 90 45 / 60 90 45 64.9
Plant steam to jacket 300 / 300 100 / 250 50 200 108.2
WFI loop trim cooler 185 / 175 55 / 70 115 120 117.5

The steam rows show a useful special case: saturated steam condenses at constant temperature, so the hot side does not change at all and both end differences are measured from the same number. That is also why steam duty is easy to control — varying the steam pressure moves the condensing temperature directly, straight off a saturated steam table.

Counterflow earns its area

Running the streams in opposite directions keeps the temperature difference more even along the length, which raises the LMTD for the same terminal temperatures and means less area for the same duty. It is also the only arrangement in which the cold outlet can exceed the hot outlet. Parallel flow starts with a large difference that collapses almost immediately and is rarely chosen deliberately.

Real exchangers are not pure counterflow. Multi-pass shell-and-tube and plate units mix directions internally, so the F correction factor scales the LMTD down to the effective value. F is always one or less, and a design sitting much below about 0.8 is usually rearranged — at that point the geometry is working against itself and a small error in a terminal temperature produces a large error in required area.

U is where the uncertainty lives

The overall coefficient is a chain of resistances in series: the film on each side, the wall, and the fouling layers. Published ranges are wide because the fouling allowance is a prediction about the future, and it frequently dominates the total.

Typical overall coefficients (BTU/hr·ft²·°F)
Service U range
Steam to water (clean) 250 to 500
Water to water 150 to 300
Steam to jacketed vessel, agitated 100 to 200
Steam to viscous liquid in a jacket 20 to 60
Water to air 5 to 15

Sizing at the optimistic end of a range produces an exchanger that makes duty on commissioning day and quietly fails to hold it a year later. On high-purity water service that matters sooner than most, because the first rouge or scale film lands directly on the resistance that was already the largest term.

Jacketed vessels deserve a caution of their own: a batch is not at steady state. As the batch warms, the driving force shrinks continuously, so a steady-state LMTD gives a valid instantaneous duty at a chosen batch temperature but not a heat-up time. We size and install these systems under high-purity water systems and CIP and SIP systems.

Frequently asked questions

What is LMTD and why is it logarithmic?

Log mean temperature difference is the correct average driving force between two streams along an exchanger. It is logarithmic because the temperature difference does not change linearly down the length: heat transfer is fastest where the streams are furthest apart, so the gap closes quickly at first and slowly afterwards. Using a simple arithmetic average of the two end differences always overstates the driving force.

How do you calculate LMTD?

Take the temperature difference at each end of the exchanger, subtract them, and divide by the natural log of their ratio. For clean steam at 250°F heating WFI from 70 to 175°F, the end differences are 75 and 180°F, giving an LMTD of about 118°F. If the two end differences are equal, the log form is undefined and the LMTD is simply that value.

What is the difference between counterflow and parallel flow?

In counterflow the streams run in opposite directions, which keeps the temperature difference more even along the length and produces a higher LMTD for the same terminal temperatures. Parallel flow starts with a huge difference that collapses quickly. Counterflow is more effective for the same area, which is why it is the default arrangement, and it is also the only arrangement that can bring the cold outlet above the hot outlet.

What is the F correction factor?

The LMTD equation assumes true counterflow. Real shell-and-tube and plate exchangers have multiple passes and mixed flow directions, so the effective driving force is lower. The F factor corrects for that geometry and is always one or less. Designs where F falls much below about 0.8 are usually reconsidered, because the arrangement is fighting itself and small temperature errors produce large area errors.

Why is the overall heat transfer coefficient so uncertain?

Because U is a series of resistances: the two film coefficients, the wall, and the fouling on both sides. The fouling allowance is an estimate of the future, and it commonly dominates. Published U ranges are broad for that reason, and a sizing done at the optimistic end of a range produces an exchanger that works on commissioning day and fails to hold duty a year later.

Does this apply to a jacketed vessel?

The same equation applies but the situation is different, because a batch in a jacketed vessel is not at steady state. The batch temperature rises as it heats, so the driving force shrinks continuously and the calculation becomes a time-dependent one. Steady-state LMTD gives a useful instantaneous answer at a chosen batch temperature, not a heat-up time.

How does fouling change what I should specify?

It sets the margin. A clean exchanger meeting duty exactly has no reserve, and on a hygienic water system the first rouge or scale layer takes it below duty. Specifying a fouling allowance appropriate to the service, rather than sizing on clean coefficients, is what keeps the unit meeting duty between cleanings rather than only when new.

Why does condensing steam simplify the calculation?

Because saturated steam condenses at constant temperature, so the hot side has no temperature change at all. Both end differences are measured from the same steam temperature, which makes the LMTD straightforward and the duty easy to control by varying steam pressure. The temperature that goes into the calculation comes straight off a steam table.

What is the NTU effectiveness method and when is it better than LMTD?

Number of Transfer Units relates the exchanger’s size to the heat capacity of the streams and yields an effectiveness, the fraction of the theoretically possible heat actually transferred. It is preferred when the outlet temperatures are unknown, because LMTD requires them as inputs. Rating an existing exchanger on a new duty is the classic NTU problem; sizing a new one for known temperatures is the classic LMTD problem.

What is approach temperature?

The gap between the outlet of one stream and the inlet of the other, and it is what drives cost. A tight approach demands a large area because the driving force in that region is small, and the area needed rises steeply as the approach closes. Specifying an unnecessarily tight approach is one of the commonest ways to make an exchanger expensive.

What is a pinch point?

The location along the exchanger where the temperature difference is at its minimum. It sets the limit on how much heat can be recovered, and it does not always sit at an end of the unit — with a phase change or a varying specific heat it can appear in the middle, which a simple end-to-end LMTD calculation will not reveal.

How do shell and tube and plate exchangers compare?

A plate exchanger gives far more area in a given volume, achieves closer approaches, and can be opened and extended. A shell and tube handles higher pressures and temperatures, tolerates fouling better and is more robust. Hygienic duties frequently use plate or specialised tubular designs because they can be cleaned and inspected.

What is a double tube sheet and why is it used in pharma?

A construction with two separated tube sheets and a vented gap between them, so a leak at either tube-to-tubesheet joint escapes to atmosphere rather than crossing between the two fluids. It is specified where cross-contamination is unacceptable, for example between plant steam or cooling water and WFI, and the vented gap makes a leak visible.

Why does fouling dominate the overall coefficient?

Because the resistances add in series and a thin fouling layer has very low conductivity. Once the film coefficients on both sides are reasonably good, they stop being the limiting term and the fouling allowance becomes the largest single resistance. That is why published U ranges are wide and why the fouling assumption deserves more scrutiny than the film calculations.

What fouling factor should I assume?

One appropriate to the service and the cleaning interval, taken from published guidance for that fluid rather than from a default. On high-purity water the relevant mechanism is usually rouge or scale rather than classic process fouling, and the cleaning regime is what keeps it in check. An exchanger sized on clean coefficients has no margin at all.

How are heat exchangers cleaned in a hygienic system?

In place where the design permits, using the same CIP chemistry and velocity rules as the rest of the loop, which requires the exchanger to be drainable and free of dead zones. Plate units can also be opened and mechanically cleaned. Any exchanger on a hygienic service has to be evaluated as part of the cleaning circuit, not as a separate item.

Why can condensate backup ruin heat exchanger performance?

Because a flooded surface transfers heat far less effectively than a condensing one. When condensate cannot drain, it blankets the lower part of the surface and the effective area falls, so the exchanger cannot hold setpoint even though the steam supply is correct. It is regularly misdiagnosed as an undersized unit.

What is stall in a steam heated exchanger?

The condition where the control valve has throttled the steam pressure so far that it can no longer push condensate through the trap against the downstream return pressure. The exchanger floods at part load, control becomes erratic, and the fix is a pumping trap or a vented arrangement rather than a larger exchanger.

Does the control valve belong on the steam side or the process side?

Usually the steam side, because varying the steam pressure moves the condensing temperature directly along the saturation curve and gives a responsive, near-isothermal control. The consequence is the stall condition above, which is why the condensate removal arrangement has to be designed alongside the control scheme.

Why does oversizing a heat exchanger cause control problems?

Because at normal load the control valve has to sit almost closed to avoid overshooting, which is exactly where its authority and resolution are worst. The loop hunts, and at low demand a steam-heated unit is also more likely to stall. An exchanger with excessive margin controls worse than one correctly sized.

What units is Q expressed in and how do I convert?

BTU per hour in the units used here, or watts in SI. One watt is about 3.412 BTU per hour. The area then follows in square feet or square metres respectively, and the overall coefficient must be in the matching set — mixing BTU-based U with a metric area is a frequent and large error.

How do I calculate the area I need?

Rearrange the duty equation: area equals duty divided by the product of the overall coefficient, the LMTD and the F factor. Every term carries uncertainty, but U is by far the least certain, so the area figure should be treated as a starting point for vendor selection rather than as a precise answer.

Does the F correction factor apply to a condensing duty?

Not in the usual sense. When one stream is condensing at constant temperature, the flow arrangement no longer affects the driving force in the way it does for two sensible-heat streams, so F is effectively one. This is another reason steam-heated duties are simpler to calculate than liquid-to-liquid ones.

What happens to LMTD if both end temperature differences are equal?

The logarithmic form divides by the log of one, which is zero, so the expression is undefined. The physical answer is simply that common value: if the driving force is the same at both ends it is the same throughout, and the log mean collapses to the arithmetic one. Calculators should handle this case explicitly rather than returning an error.

Can I use LMTD for a batch heat-up in a jacketed vessel?

Only as an instantaneous value. The batch temperature rises continuously, so the driving force shrinks as the heat-up proceeds and no single LMTD describes the whole operation. Heat-up time comes from integrating over the batch temperature range, which is a different calculation using the same underlying equation.